Solve for x x/3+10>=15

$\frac{x}{3} + 10 \geq 15$

Step 1

Move all terms not containing $x$ to the right side of the inequality.

Subtract $10$ from both sides of the inequality.

$\frac{x}{3} \geq 15 - 10$

Subtract $10$ from $15$ .

$\frac{x}{3} \geq 5$

Step 2

Multiply both sides by $3$ .

$\frac{x}{3} \cdot 3 \geq 5 \cdot 3$

Step 3

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{x}{3} \cdot 3 \geq 5 \cdot 3$

Rewrite the expression.

$x \geq 5 \cdot 3$

Simplify the right side.

Multiply $5$ by $3$ .

$x \geq 15$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \geq 15$

Interval Notation:

$[15, \infty)$