Solve for x (x-3)-2(x+6)=-5

$(x - 3) - 2 (x + 6) = - 5$

Step 1

Simplify $x - 3 - 2 (x + 6)$ .

Simplify each term.

Apply the distributive property.

$x - 3 - 2 x - 2 \cdot 6 = - 5$

Multiply $- 2$ by $6$ .

$x - 3 - 2 x - 12 = - 5$

Simplify by adding terms.

Subtract $2 x$ from $x$ .

$- x - 3 - 12 = - 5$

Subtract $12$ from $- 3$ .

$- x - 15 = - 5$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Add $15$ to both sides of the equation.

$- x = - 5 + 15$

Add $- 5$ and $15$ .

$- x = 10$

Step 3

Divide each term in $- x = 10$ by $- 1$ and simplify.

Divide each term in $- x = 10$ by $- 1$ .

$\frac{- x}{- 1} = \frac{10}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{10}{- 1}$

Divide $x$ by $1$ .

$x = \frac{10}{- 1}$

Simplify the right side.

Divide $10$ by $- 1$ .

$x = - 10$