Solve for x x^3-7X-6=0

$x^{3} - 7 X - 6 = 0$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Add $7 X$ to both sides of the equation.

$x^{3} - 6 = 7 X$

Add $6$ to both sides of the equation.

$x^{3} = 7 X + 6$

Step 2

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[3]{7 X + 6}$