Solve for x x+3 = square root of 12x+1

$x + 3 = \sqrt{12 x + 1}$

Step 1

Since the radical is on the right side of the equation, switch the sides so it is on the left side of the equation.

$\sqrt{12 x + 1} = x + 3$

Step 2

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{12 x + 1}}^{2} = {(x + 3)}^{2}$

Step 3

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{12 x + 1}$ as ${(12 x + 1)}^{\frac{1}{2}}$ .

${({(12 x + 1)}^{\frac{1}{2}})}^{2} = {(x + 3)}^{2}$

Simplify the left side.

Simplify ${({(12 x + 1)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(12 x + 1)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(12 x + 1)}^{\frac{1}{2} \cdot 2} = {(x + 3)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(12 x + 1)}^{\frac{1}{2} \cdot 2} = {(x + 3)}^{2}$

Rewrite the expression.

${(12 x + 1)}^{1} = {(x + 3)}^{2}$

Simplify.

$12 x + 1 = {(x + 3)}^{2}$

Simplify the right side.

Simplify ${(x + 3)}^{2}$ .

Rewrite ${(x + 3)}^{2}$ as $(x + 3) (x + 3)$ .

$12 x + 1 = (x + 3) (x + 3)$

Expand $(x + 3) (x + 3)$ using the FOIL Method.

Apply the distributive property.

$12 x + 1 = x (x + 3) + 3 (x + 3)$

Apply the distributive property.

$12 x + 1 = x \cdot x + x \cdot 3 + 3 (x + 3)$

Apply the distributive property.

$12 x + 1 = x \cdot x + x \cdot 3 + 3 x + 3 \cdot 3$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$12 x + 1 = x^{2} + x \cdot 3 + 3 x + 3 \cdot 3$

Move $3$ to the left of $x$ .

$12 x + 1 = x^{2} + 3 \cdot x + 3 x + 3 \cdot 3$

Multiply $3$ by $3$ .

$12 x + 1 = x^{2} + 3 x + 3 x + 9$

Add $3 x$ and $3 x$ .

$12 x + 1 = x^{2} + 6 x + 9$

Step 4

Solve for $x$ .

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x^{2} + 6 x + 9 = 12 x + 1$

Move all terms containing $x$ to the left side of the equation.

Subtract $12 x$ from both sides of the equation.

$x^{2} + 6 x + 9 - 12 x = 1$

Subtract $12 x$ from $6 x$ .

$x^{2} - 6 x + 9 = 1$

Subtract $1$ from both sides of the equation.

$x^{2} - 6 x + 9 - 1 = 0$

Subtract $1$ from $9$ .

$x^{2} - 6 x + 8 = 0$

Factor $x^{2} - 6 x + 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $8$ and whose sum is $- 6$ .

$- 4, - 2$

Write the factored form using these integers.

$(x - 4) (x - 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 4 = 0$

$x - 2 = 0$

Set $x - 4$ equal to $0$ and solve for $x$ .

Set $x - 4$ equal to $0$ .

$x - 4 = 0$

Add $4$ to both sides of the equation.

$x = 4$

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

The final solution is all the values that make $(x - 4) (x - 2) = 0$ true.

$x = 4, 2$

Solve for x x+3 = square root of 12x+1

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