Solve for x ((x-3)(x+4))/(x-3)=0

$\frac{(x - 3) (x + 4)}{x - 3} = 0$

Step 1

Set the numerator equal to zero.

$(x - 3) (x + 4) = 0$

Step 2

Solve the equation for $x$ .

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 3 = 0$

$x + 4 = 0$

Set $x - 3$ equal to $0$ and solve for $x$ .

Set $x - 3$ equal to $0$ .

$x - 3 = 0$

Add $3$ to both sides of the equation.

$x = 3$

Set $x + 4$ equal to $0$ and solve for $x$ .

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Subtract $4$ from both sides of the equation.

$x = - 4$

The final solution is all the values that make $(x - 3) (x + 4) = 0$ true.

$x = 3, - 4$

Step 3

Exclude the solutions that do not make $\frac{(x - 3) (x + 4)}{x - 3} = 0$ true.

$x = - 4$