Solve for x -x+3y=6

$- x + 3 y = 6$

Step 1

Subtract $3 y$ from both sides of the equation.

$- x = 6 - 3 y$

Step 2

Divide each term in $- x = 6 - 3 y$ by $- 1$ and simplify.

Divide each term in $- x = 6 - 3 y$ by $- 1$ .

$\frac{- x}{- 1} = \frac{6}{- 1} + \frac{- 3 y}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{6}{- 1} + \frac{- 3 y}{- 1}$

Divide $x$ by $1$ .

$x = \frac{6}{- 1} + \frac{- 3 y}{- 1}$

Simplify the right side.

Simplify each term.

Divide $6$ by $- 1$ .

$x = - 6 + \frac{- 3 y}{- 1}$

Move the negative one from the denominator of $\frac{- 3 y}{- 1}$ .

$x = - 6 - 1 \cdot (- 3 y)$

Rewrite $- 1 \cdot (- 3 y)$ as $- (- 3 y)$ .

$x = - 6 - (- 3 y)$

Multiply $- 3$ by $- 1$ .

$x = - 6 + 3 y$