Solve for x x-4(2x-1)=-3(2x+1)-x

$x - 4 (2 x - 1) = - 3 (2 x + 1) - x$

Simplify $x - 4 (2 x - 1)$ .

Simplify each term.

Apply the distributive property.

$x - 4 (2 x) - 4 \cdot - 1 = - 3 (2 x + 1) - x$

Multiply $2$ by $- 4$ .

$x - 8 x - 4 \cdot - 1 = - 3 (2 x + 1) - x$

Multiply $- 4$ by $- 1$ .

$x - 8 x + 4 = - 3 (2 x + 1) - x$

Subtract $8 x$ from $x$ .

$- 7 x + 4 = - 3 (2 x + 1) - x$

Simplify $- 3 (2 x + 1) - x$ .

Simplify each term.

Apply the distributive property.

$- 7 x + 4 = - 3 (2 x) - 3 \cdot 1 - x$

Multiply $2$ by $- 3$ .

$- 7 x + 4 = - 6 x - 3 \cdot 1 - x$

Multiply $- 3$ by $1$ .

$- 7 x + 4 = - 6 x - 3 - x$

Subtract $x$ from $- 6 x$ .

$- 7 x + 4 = - 7 x - 3$

Move all terms containing $x$ to the left side of the equation.

Add $7 x$ to both sides of the equation.

$- 7 x + 4 + 7 x = - 3$

Combine the opposite terms in $- 7 x + 4 + 7 x$ .

Add $- 7 x$ and $7 x$ .

$0 + 4 = - 3$

Add $0$ and $4$ .

$4 = - 3$

Since $4 \neq - 3$ , there are no solutions.

No solution