Solve for x x/4-3=2x+1

$\frac{x}{4} - 3 = 2 x + 1$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$\frac{x}{4} - 3 - 2 x = 1$

To write $- 2 x$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{x}{4} - 2 x \cdot \frac{4}{4} - 3 = 1$

Combine $- 2 x$ and $\frac{4}{4}$ .

$\frac{x}{4} + \frac{- 2 x \cdot 4}{4} - 3 = 1$

Combine the numerators over the common denominator.

$\frac{x - 2 x \cdot 4}{4} - 3 = 1$

Simplify each term.

Simplify the numerator.

Factor $x$ out of $x - 2 x \cdot 4$ .

Raise $x$ to the power of $1$ .

$\frac{x^{1} - 2 x \cdot 4}{4} - 3 = 1$

Factor $x$ out of $x^{1}$ .

$\frac{x \cdot 1 - 2 x \cdot 4}{4} - 3 = 1$

Factor $x$ out of $- 2 x \cdot 4$ .

$\frac{x \cdot 1 + x (- 2 \cdot 4)}{4} - 3 = 1$

Factor $x$ out of $x \cdot 1 + x (- 2 \cdot 4)$ .

$\frac{x (1 - 2 \cdot 4)}{4} - 3 = 1$

Multiply $- 2$ by $4$ .

$\frac{x (1 - 8)}{4} - 3 = 1$

Subtract $8$ from $1$ .

$\frac{x \cdot - 7}{4} - 3 = 1$

Move $- 7$ to the left of $x$ .

$\frac{- 7 \cdot x}{4} - 3 = 1$

Move the negative in front of the fraction.

$- \frac{7 x}{4} - 3 = 1$

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$- \frac{7 x}{4} = 1 + 3$

Add $1$ and $3$ .

$- \frac{7 x}{4} = 4$

Multiply both sides of the equation by $- \frac{4}{7}$ .

$- \frac{4}{7} (- \frac{7 x}{4}) = - \frac{4}{7} \cdot 4$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{4}{7} (- \frac{7 x}{4})$ .

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{4}{7}$ into the numerator.

$\frac{- 4}{7} (- \frac{7 x}{4}) = - \frac{4}{7} \cdot 4$

Move the leading negative in $- \frac{7 x}{4}$ into the numerator.

$\frac{- 4}{7} \cdot \frac{- 7 x}{4} = - \frac{4}{7} \cdot 4$

Factor $4$ out of $- 4$ .

$\frac{4 (- 1)}{7} \cdot \frac{- 7 x}{4} = - \frac{4}{7} \cdot 4$

Cancel the common factor.

$\frac{4 \cdot - 1}{7} \cdot \frac{- 7 x}{4} = - \frac{4}{7} \cdot 4$

Rewrite the expression.

$\frac{- 1}{7} (- 7 x) = - \frac{4}{7} \cdot 4$

Cancel the common factor of $7$ .

Factor $7$ out of $- 7 x$ .

$\frac{- 1}{7} (7 (- x)) = - \frac{4}{7} \cdot 4$

Cancel the common factor.

$\frac{- 1}{7} (7 (- x)) = - \frac{4}{7} \cdot 4$

Rewrite the expression.

$- - x = - \frac{4}{7} \cdot 4$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{4}{7} \cdot 4$

Multiply $x$ by $1$ .

$x = - \frac{4}{7} \cdot 4$

Simplify the right side.

Simplify $- \frac{4}{7} \cdot 4$ .

Multiply $- \frac{4}{7} \cdot 4$ .

Multiply $4$ by $- 1$ .

$x = - 4 (\frac{4}{7})$

Combine $- 4$ and $\frac{4}{7}$ .

$x = \frac{- 4 \cdot 4}{7}$

Multiply $- 4$ by $4$ .

$x = \frac{- 16}{7}$

Move the negative in front of the fraction.

$x = - \frac{16}{7}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{16}{7}$

Decimal Form:

$x = - 2.\overline{285714}$

Mixed Number Form:

$x = - 2 \frac{2}{7}$

Solve for x x/4-3=2x+1

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