Solve for x x-4(x+1)=-3(x+1)+1

$x - 4 (x + 1) = - 3 (x + 1) + 1$

Step 1

Simplify $x - 4 (x + 1)$ .

Simplify each term.

Apply the distributive property.

$x - 4 x - 4 \cdot 1 = - 3 (x + 1) + 1$

Multiply $- 4$ by $1$ .

$x - 4 x - 4 = - 3 (x + 1) + 1$

Subtract $4 x$ from $x$ .

$- 3 x - 4 = - 3 (x + 1) + 1$

Step 2

Simplify $- 3 (x + 1) + 1$ .

Simplify each term.

Apply the distributive property.

$- 3 x - 4 = - 3 x - 3 \cdot 1 + 1$

Multiply $- 3$ by $1$ .

$- 3 x - 4 = - 3 x - 3 + 1$

Add $- 3$ and $1$ .

$- 3 x - 4 = - 3 x - 2$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$- 3 x - 4 + 3 x = - 2$

Combine the opposite terms in $- 3 x - 4 + 3 x$ .

Add $- 3 x$ and $3 x$ .

$0 - 4 = - 2$

Subtract $4$ from $0$ .

$- 4 = - 2$

Step 4

Since $- 4 \neq - 2$ , there are no solutions.

No solution