Solve for x (x-5)^2=4

${(x - 5)}^{2} = 4$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x - 5 = \pm \sqrt{4}$

Step 2

Simplify $\pm \sqrt{4}$ .

Rewrite $4$ as $2^{2}$ .

$x - 5 = \pm \sqrt{2^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$x - 5 = \pm 2$

Step 3

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x - 5 = 2$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$x = 2 + 5$

Add $2$ and $5$ .

$x = 7$

Next, use the negative value of the $\pm$ to find the second solution.

$x - 5 = - 2$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$x = - 2 + 5$

Add $- 2$ and $5$ .

$x = 3$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 7, 3$