Solve for x x-5(x+1)=3x+2

$x - 5 (x + 1) = 3 x + 2$

Simplify $x - 5 (x + 1)$ .

Simplify each term.

Apply the distributive property.

$x - 5 x - 5 \cdot 1 = 3 x + 2$

Multiply $- 5$ by $1$ .

$x - 5 x - 5 = 3 x + 2$

Subtract $5 x$ from $x$ .

$- 4 x - 5 = 3 x + 2$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$- 4 x - 5 - 3 x = 2$

Subtract $3 x$ from $- 4 x$ .

$- 7 x - 5 = 2$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$- 7 x = 2 + 5$

Add $2$ and $5$ .

$- 7 x = 7$

Divide each term in $- 7 x = 7$ by $- 7$ and simplify.

Divide each term in $- 7 x = 7$ by $- 7$ .

$\frac{- 7 x}{- 7} = \frac{7}{- 7}$

Simplify the left side.

Cancel the common factor of $- 7$ .

Cancel the common factor.

$\frac{- 7 x}{- 7} = \frac{7}{- 7}$

Divide $x$ by $1$ .

$x = \frac{7}{- 7}$

Simplify the right side.

Divide $7$ by $- 7$ .

$x = - 1$