Solve for x x+5x+4=3(2x-1)

$x + 5 x + 4 = 3 (2 x - 1)$

Add $x$ and $5 x$ .

$6 x + 4 = 3 (2 x - 1)$

Simplify $3 (2 x - 1)$ .

Apply the distributive property.

$6 x + 4 = 3 (2 x) + 3 \cdot - 1$

Multiply.

Multiply $2$ by $3$ .

$6 x + 4 = 6 x + 3 \cdot - 1$

Multiply $3$ by $- 1$ .

$6 x + 4 = 6 x - 3$

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$6 x + 4 - 6 x = - 3$

Combine the opposite terms in $6 x + 4 - 6 x$ .

Subtract $6 x$ from $6 x$ .

$0 + 4 = - 3$

Add $0$ and $4$ .

$4 = - 3$

Since $4 \neq - 3$ , there are no solutions.

No solution