Solve for x -x/6>=3

$- \frac{x}{6} \geq 3$

Step 1

Divide each term in $- \frac{x}{6} \geq 3$ by $- 1$ and simplify.

Divide each term in $- \frac{x}{6} \geq 3$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- \frac{x}{6}}{- 1} \leq \frac{3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{\frac{x}{6}}{1} \leq \frac{3}{- 1}$

Divide $\frac{x}{6}$ by $1$ .

$\frac{x}{6} \leq \frac{3}{- 1}$

Simplify the right side.

Divide $3$ by $- 1$ .

$\frac{x}{6} \leq - 3$

Step 2

Multiply both sides by $6$ .

$\frac{x}{6} \cdot 6 \leq - 3 \cdot 6$

Step 3

Simplify.

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{x}{6} \cdot 6 \leq - 3 \cdot 6$

Rewrite the expression.

$x \leq - 3 \cdot 6$

Simplify the right side.

Multiply $- 3$ by $6$ .

$x \leq - 18$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 18$

Interval Notation:

$(- \infty, - 18]$

Solve for x -x/6>=3

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