Solve for x x+6-5=8-2

$x + 6 - 5 = 8 - 2$

Subtract $5$ from $6$ .

$x + 1 = 8 - 2$

Subtract $2$ from $8$ .

$x + 1 = 6$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$x = 6 - 1$

Subtract $1$ from $6$ .

$x = 5$