Solve for x |x+6|>=6

$| x + 6 | \geq 6$

Step 1

Write $| x + 6 | \geq 6$ as a piecewise.

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$x + 6 \geq 0$

Subtract $6$ from both sides of the inequality.

$x \geq - 6$

In the piece where $x + 6$ is non-negative, remove the absolute value.

$x + 6 \geq 6$

To find the interval for the second piece, find where the inside of the absolute value is negative.

$x + 6 < 0$

Subtract $6$ from both sides of the inequality.

$x < - 6$

In the piece where $x + 6$ is negative, remove the absolute value and multiply by $- 1$ .

$- (x + 6) \geq 6$

Write as a piecewise.

${\begin{cases} x + 6 \geq 6 & x \geq - 6 \\ - (x + 6) \geq 6 & x < - 6 \end{cases}$

Simplify $- (x + 6) \geq 6$ .

Apply the distributive property.

${\begin{cases} x + 6 \geq 6 & x \geq - 6 \\ - x - 1 \cdot 6 \geq 6 & x < - 6 \end{cases}$

Multiply $- 1$ by $6$ .

${\begin{cases} x + 6 \geq 6 & x \geq - 6 \\ - x - 6 \geq 6 & x < - 6 \end{cases}$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $6$ from both sides of the inequality.

$x \geq 6 - 6$

Subtract $6$ from $6$ .

$x \geq 0$

Step 3

Solve $- x - 6 \geq 6$ for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Add $6$ to both sides of the inequality.

$- x \geq 6 + 6$

Add $6$ and $6$ .

$- x \geq 12$

Divide each term in $- x \geq 12$ by $- 1$ and simplify.

Divide each term in $- x \geq 12$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} \leq \frac{12}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} \leq \frac{12}{- 1}$

Divide $x$ by $1$ .

$x \leq \frac{12}{- 1}$

Simplify the right side.

Divide $12$ by $- 1$ .

$x \leq - 12$

Step 4

Find the union of the solutions.

$x \leq - 12$ or $x \geq 0$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 12 or x \geq 0$

Interval Notation:

$(- \infty, - 12] \cup [0, \infty)$

Step 6

Solve for x |x+6|>=6

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