Solve for x x-6-x-4=10-x

$x - 6 - x - 4 = 10 - x$

Step 1

Simplify $x - 6 - x - 4$ .

Combine the opposite terms in $x - 6 - x - 4$ .

Subtract $x$ from $x$ .

$0 - 6 - 4 = 10 - x$

Subtract $6$ from $0$ .

$- 6 - 4 = 10 - x$

Subtract $4$ from $- 6$ .

$- 10 = 10 - x$

Step 2

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$10 - x = - 10$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$- x = - 10 - 10$

Subtract $10$ from $- 10$ .

$- x = - 20$

Step 4

Divide each term in $- x = - 20$ by $- 1$ and simplify.

Divide each term in $- x = - 20$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 20}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 20}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 20}{- 1}$

Simplify the right side.

Divide $- 20$ by $- 1$ .

$x = 20$