Solve for x x/9>=3

$\frac{x}{9} \geq 3$

Step 1

Multiply both sides by $9$ .

$\frac{x}{9} \cdot 9 \geq 3 \cdot 9$

Step 2

Simplify.

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{x}{9} \cdot 9 \geq 3 \cdot 9$

Rewrite the expression.

$x \geq 3 \cdot 9$

$x \geq 3 \cdot 9$

$x \geq 3 \cdot 9$

Simplify the right side.

Multiply $3$ by $9$ .

$x \geq 27$

$x \geq 27$

$x \geq 27$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x \geq 27$

Interval Notation:

$[27, \infty)$

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