Solve for x x/9+7>=10

$\frac{x}{9} + 7 \geq 10$

Step 1

Move all terms not containing $x$ to the right side of the inequality.

Subtract $7$ from both sides of the inequality.

$\frac{x}{9} \geq 10 - 7$

Subtract $7$ from $10$ .

$\frac{x}{9} \geq 3$

Step 2

Multiply both sides by $9$ .

$\frac{x}{9} \cdot 9 \geq 3 \cdot 9$

Step 3

Simplify.

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{x}{9} \cdot 9 \geq 3 \cdot 9$

Rewrite the expression.

$x \geq 3 \cdot 9$

Simplify the right side.

Multiply $3$ by $9$ .

$x \geq 27$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \geq 27$

Interval Notation:

$[27, \infty)$