Solve for x (x+9)(x-3)=(x+1)^2

$(x + 9) (x - 3) = {(x + 1)}^{2}$

Step 1

Simplify $(x + 9) (x - 3)$ .

Rewrite.

$0 + 0 + (x + 9) (x - 3) = {(x + 1)}^{2}$

Simplify by adding zeros.

$(x + 9) (x - 3) = {(x + 1)}^{2}$

Expand $(x + 9) (x - 3)$ using the FOIL Method.

Apply the distributive property.

$x (x - 3) + 9 (x - 3) = {(x + 1)}^{2}$

Apply the distributive property.

$x \cdot x + x \cdot - 3 + 9 (x - 3) = {(x + 1)}^{2}$

Apply the distributive property.

$x \cdot x + x \cdot - 3 + 9 x + 9 \cdot - 3 = {(x + 1)}^{2}$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 3 + 9 x + 9 \cdot - 3 = {(x + 1)}^{2}$

Move $- 3$ to the left of $x$ .

$x^{2} - 3 \cdot x + 9 x + 9 \cdot - 3 = {(x + 1)}^{2}$

Multiply $9$ by $- 3$ .

$x^{2} - 3 x + 9 x - 27 = {(x + 1)}^{2}$

Add $- 3 x$ and $9 x$ .

$x^{2} + 6 x - 27 = {(x + 1)}^{2}$

Step 2

Simplify ${(x + 1)}^{2}$ .

Rewrite ${(x + 1)}^{2}$ as $(x + 1) (x + 1)$ .

$x^{2} + 6 x - 27 = (x + 1) (x + 1)$

Expand $(x + 1) (x + 1)$ using the FOIL Method.

Apply the distributive property.

$x^{2} + 6 x - 27 = x (x + 1) + 1 (x + 1)$

Apply the distributive property.

$x^{2} + 6 x - 27 = x \cdot x + x \cdot 1 + 1 (x + 1)$

Apply the distributive property.

$x^{2} + 6 x - 27 = x \cdot x + x \cdot 1 + 1 x + 1 \cdot 1$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + 6 x - 27 = x^{2} + x \cdot 1 + 1 x + 1 \cdot 1$

Multiply $x$ by $1$ .

$x^{2} + 6 x - 27 = x^{2} + x + 1 x + 1 \cdot 1$

Multiply $x$ by $1$ .

$x^{2} + 6 x - 27 = x^{2} + x + x + 1 \cdot 1$

Multiply $1$ by $1$ .

$x^{2} + 6 x - 27 = x^{2} + x + x + 1$

Add $x$ and $x$ .

$x^{2} + 6 x - 27 = x^{2} + 2 x + 1$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $x^{2}$ from both sides of the equation.

$x^{2} + 6 x - 27 - x^{2} = 2 x + 1$

Subtract $2 x$ from both sides of the equation.

$x^{2} + 6 x - 27 - x^{2} - 2 x = 1$

Combine the opposite terms in $x^{2} + 6 x - 27 - x^{2} - 2 x$ .

Subtract $x^{2}$ from $x^{2}$ .

$6 x - 27 + 0 - 2 x = 1$

Add $6 x - 27$ and $0$ .

$6 x - 27 - 2 x = 1$

Subtract $2 x$ from $6 x$ .

$4 x - 27 = 1$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $27$ to both sides of the equation.

$4 x = 1 + 27$

Add $1$ and $27$ .

$4 x = 28$

Step 5

Divide each term in $4 x = 28$ by $4$ and simplify.

Divide each term in $4 x = 28$ by $4$ .

$\frac{4 x}{4} = \frac{28}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{28}{4}$

Divide $x$ by $1$ .

$x = \frac{28}{4}$

Simplify the right side.

Divide $28$ by $4$ .

$x = 7$

Solve for x (x+9)(x-3)=(x+1)^2

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