Solve for x x=(-b+- square root of b^2-4ac)/(2a)

$x = \frac{- b + - \sqrt{b^{2} - 4 a c}}{2 a}$

Step 1

Replace all occurrences of $+$ $-$ with a single $-$ . A plus sign followed by a minus sign has the same mathematical meaning as a single minus sign because $1 \cdot - 1 = - 1$

$x = \frac{- b - \sqrt{b^{2} - 4 a c}}{2 a}$

Step 2

Factor $- 1$ out of $- b$ .

$x = \frac{- (b) - \sqrt{b^{2} - 4 a c}}{2 a}$

Step 3

Factor $- 1$ out of $- \sqrt{b^{2} - 4 a c}$ .

$x = \frac{- (b) - (\sqrt{b^{2} - 4 a c})}{2 a}$

Step 4

Factor $- 1$ out of $- (b) - (\sqrt{b^{2} - 4 a c})$ .

$x = \frac{- (b + \sqrt{b^{2} - 4 a c})}{2 a}$

Step 5

Simplify the expression.

Rewrite $- (b + \sqrt{b^{2} - 4 a c})$ as $- 1 (b + \sqrt{b^{2} - 4 a c})$ .

$x = \frac{- 1 (b + \sqrt{b^{2} - 4 a c})}{2 a}$

Move the negative in front of the fraction.

$x = - \frac{b + \sqrt{b^{2} - 4 a c}}{2 a}$

Solve for x x=(-b+- square root of b^2-4ac)/(2a)

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