Solve for x x = log base 2 of 1/16

$x = \log_{2} (\frac{1}{16})$

Step 1

Rewrite as an equation.

$x = \log_{2} (\frac{1}{16}) = x$

Step 2

Rewrite $\log_{2} (\frac{1}{16}) = x$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b$ does not equal $1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$x = 2^{x} = \frac{1}{16}$

Step 3

Create equivalent expressions in the equation that all have equal bases.

$x = 2^{x} = 2^{- 4}$

Step 4

Since the bases are the same, the two expressions are only equal if the exponents are also equal.

$x = x = - 4$

Step 5

The variable $x$ is equal to $- 4$ .

$x = - 4$

Solve for x x = log base 2 of 1/16

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