Solve for x (x)+(x+3)+(x-2)+3(x+3)-1=87

$(x) + (x + 3) + (x - 2) + 3 (x + 3) - 1 = 87$

Step 1

Simplify $x + x + 3 + x - 2 + 3 (x + 3) - 1$ .

Simplify each term.

Apply the distributive property.

$x + x + 3 + x - 2 + 3 x + 3 \cdot 3 - 1 = 87$

Multiply $3$ by $3$ .

$x + x + 3 + x - 2 + 3 x + 9 - 1 = 87$

Simplify by adding terms.

Add $x$ and $x$ .

$2 x + 3 + x - 2 + 3 x + 9 - 1 = 87$

Add $2 x$ and $x$ .

$3 x + 3 - 2 + 3 x + 9 - 1 = 87$

Add $3 x$ and $3 x$ .

$6 x + 3 - 2 + 9 - 1 = 87$

Subtract $2$ from $3$ .

$6 x + 1 + 9 - 1 = 87$

Combine the opposite terms in $6 x + 1 + 9 - 1$ .

Subtract $1$ from $1$ .

$6 x + 0 + 9 = 87$

Add $6 x$ and $0$ .

$6 x + 9 = 87$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $9$ from both sides of the equation.

$6 x = 87 - 9$

Subtract $9$ from $87$ .

$6 x = 78$

Step 3

Divide each term in $6 x = 78$ by $6$ and simplify.

Divide each term in $6 x = 78$ by $6$ .

$\frac{6 x}{6} = \frac{78}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{78}{6}$

Divide $x$ by $1$ .

$x = \frac{78}{6}$

Simplify the right side.

Divide $78$ by $6$ .

$x = 13$