Solve for x y=1/3(x+2)

$y = \frac{1}{3} (x + 2)$

Step 1

Rewrite the equation as $\frac{1}{3} \cdot (x + 2) = y$ .

$\frac{1}{3} \cdot (x + 2) = y$

Step 2

Multiply both sides of the equation by $3$ .

$3 (\frac{1}{3} \cdot (x + 2)) = 3 y$

Step 3

Simplify the left side.

Simplify $3 (\frac{1}{3} \cdot (x + 2))$ .

Apply the distributive property.

$3 (\frac{1}{3} x + \frac{1}{3} \cdot 2) = 3 y$

Combine $\frac{1}{3}$ and $x$ .

$3 (\frac{x}{3} + \frac{1}{3} \cdot 2) = 3 y$

Combine $\frac{1}{3}$ and $2$ .

$3 (\frac{x}{3} + \frac{2}{3}) = 3 y$

Apply the distributive property.

$3 \frac{x}{3} + 3 (\frac{2}{3}) = 3 y$

Cancel the common factor of $3$ .

Cancel the common factor.

$3 \frac{x}{3} + 3 (\frac{2}{3}) = 3 y$

Rewrite the expression.

$x + 3 (\frac{2}{3}) = 3 y$

$x + 3 (\frac{2}{3}) = 3 y$

Cancel the common factor of $3$ .

Cancel the common factor.

$x + 3 (\frac{2}{3}) = 3 y$

Rewrite the expression.

$x + 2 = 3 y$

$x + 2 = 3 y$

$x + 2 = 3 y$

$x + 2 = 3 y$

Step 4

Subtract $2$ from both sides of the equation.

$x = 3 y - 2$

Related Questions