Solve for x y=-2-x+3

$y = - 2 - x + 3$

Step 1

Rewrite the equation as $- 2 - x + 3 = y$ .

$- 2 - x + 3 = y$

Step 2

Add $- 2$ and $3$ .

$- x + 1 = y$

Step 3

Subtract $1$ from both sides of the equation.

$- x = y - 1$

Step 4

Divide each term in $- x = y - 1$ by $- 1$ and simplify.

Divide each term in $- x = y - 1$ by $- 1$ .

$\frac{- x}{- 1} = \frac{y}{- 1} + \frac{- 1}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{y}{- 1} + \frac{- 1}{- 1}$

Divide $x$ by $1$ .

$x = \frac{y}{- 1} + \frac{- 1}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{y}{- 1}$ .

$x = - 1 \cdot y + \frac{- 1}{- 1}$

Rewrite $- 1 \cdot y$ as $- y$ .

$x = - y + \frac{- 1}{- 1}$

Divide $- 1$ by $- 1$ .

$x = - y + 1$