Solve for x y=(x-5)^3-1

$y = {(x - 5)}^{3} - 1$

Step 1

Rewrite the equation as ${(x - 5)}^{3} - 1 = y$ .

${(x - 5)}^{3} - 1 = y$

Step 2

Add $1$ to both sides of the equation.

${(x - 5)}^{3} = y + 1$

Step 3

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

$x - 5 = \sqrt[3]{y + 1}$

Step 4

Add $5$ to both sides of the equation.

$x = \sqrt[3]{y + 1} + 5$