Solve for x y-y_1=m(x-x_1) for x

$y - y_{1} = m (x - x_{1})$ for $x$

Rewrite the equation as $m (x - x) = y - y$ .

$m (x - x) = y - y$

Simplify $m (x - x)$ .

Subtract $x$ from $x$ .

$m \cdot 0 = y - y$

Multiply $m$ by $0$ .

$0 = y - y$

$0 = y - y$

Subtract $y$ from $y$ .

$0 = 0$

Since $0 = 0$ , the equation will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$

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