Solve for x2 (2(x_1-x_2))/m=B

$\frac{2 (x_{1} - x_{2})}{m} = B$

Step 1

Multiply both sides by $m$ .

$\frac{2 (x_{1} - x_{2})}{m} m = B m$

Step 2

Simplify the left side.

Simplify $\frac{2 (x_{1} - x_{2})}{m} m$ .

Cancel the common factor of $m$ .

Cancel the common factor.

$\frac{2 (x_{1} - x_{2})}{m} m = B m$

Rewrite the expression.

$2 (x_{1} - x_{2}) = B m$

Apply the distributive property.

$2 x_{1} + 2 (- x_{2}) = B m$

Multiply $- 1$ by $2$ .

$2 x_{1} - 2 x_{2} = B m$

Step 3

Solve for $x_{1}$ .

Add $2 x_{2}$ to both sides of the equation.

$2 x_{1} = B m + 2 x_{2}$

Divide each term in $2 x_{1} = B m + 2 x_{2}$ by $2$ and simplify.

Divide each term in $2 x_{1} = B m + 2 x_{2}$ by $2$ .

$\frac{2 x_{1}}{2} = \frac{B m}{2} + \frac{2 x_{2}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x_{1}}{2} = \frac{B m}{2} + \frac{2 x_{2}}{2}$

Divide $x_{1}$ by $1$ .

$x_{1} = \frac{B m}{2} + \frac{2 x_{2}}{2}$

Simplify the right side.

Cancel the common factor of $2$ .

Cancel the common factor.

$x_{1} = \frac{B m}{2} + \frac{2 x_{2}}{2}$

Divide $x_{2}$ by $1$ .

$x_{1} = \frac{B m}{2} + x_{2}$