Solve for x2 (5(x_1-x_2))/m=b

$\frac{5 (x_{1} - x_{2})}{m} = b$

Multiply both sides by $m$ .

$\frac{5 (x_{1} - x_{2})}{m} m = b m$

Simplify the left side.

Simplify $\frac{5 (x_{1} - x_{2})}{m} m$ .

Cancel the common factor of $m$ .

Cancel the common factor.

$\frac{5 (x_{1} - x_{2})}{m} m = b m$

Rewrite the expression.

$5 (x_{1} - x_{2}) = b m$

Apply the distributive property.

$5 x_{1} + 5 (- x_{2}) = b m$

Multiply $- 1$ by $5$ .

$5 x_{1} - 5 x_{2} = b m$

Solve for $x_{1}$ .

Add $5 x_{2}$ to both sides of the equation.

$5 x_{1} = b m + 5 x_{2}$

Divide each term in $5 x_{1} = b m + 5 x_{2}$ by $5$ and simplify.

Divide each term in $5 x_{1} = b m + 5 x_{2}$ by $5$ .

$\frac{5 x_{1}}{5} = \frac{b m}{5} + \frac{5 x_{2}}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x_{1}}{5} = \frac{b m}{5} + \frac{5 x_{2}}{5}$

Divide $x_{1}$ by $1$ .

$x_{1} = \frac{b m}{5} + \frac{5 x_{2}}{5}$

Simplify the right side.

Cancel the common factor of $5$ .

Cancel the common factor.

$x_{1} = \frac{b m}{5} + \frac{5 x_{2}}{5}$

Divide $x_{2}$ by $1$ .

$x_{1} = \frac{b m}{5} + x_{2}$