Solve for y 1/3(21y+39)=-36

$\frac{1}{3} (21 y + 39) = - 36$

Multiply both sides of the equation by $3$ .

$3 (\frac{1}{3} \cdot (21 y + 39)) = 3 \cdot - 36$

Simplify both sides of the equation.

Simplify the left side.

Simplify $3 (\frac{1}{3} \cdot (21 y + 39))$ .

Apply the distributive property.

$3 (\frac{1}{3} (21 y) + \frac{1}{3} \cdot 39) = 3 \cdot - 36$

Cancel the common factor of $3$ .

Factor $3$ out of $21 y$ .

$3 (\frac{1}{3} (3 (7 y)) + \frac{1}{3} \cdot 39) = 3 \cdot - 36$

Cancel the common factor.

$3 (\frac{1}{3} (3 (7 y)) + \frac{1}{3} \cdot 39) = 3 \cdot - 36$

Rewrite the expression.

$3 (7 y + \frac{1}{3} \cdot 39) = 3 \cdot - 36$

Cancel the common factor of $3$ .

Factor $3$ out of $39$ .

$3 (7 y + \frac{1}{3} \cdot (3 (13))) = 3 \cdot - 36$

Cancel the common factor.

$3 (7 y + \frac{1}{3} \cdot (3 \cdot 13)) = 3 \cdot - 36$

Rewrite the expression.

$3 (7 y + 13) = 3 \cdot - 36$

Apply the distributive property.

$3 (7 y) + 3 \cdot 13 = 3 \cdot - 36$

Multiply.

Multiply $7$ by $3$ .

$21 y + 3 \cdot 13 = 3 \cdot - 36$

Multiply $3$ by $13$ .

$21 y + 39 = 3 \cdot - 36$

Simplify the right side.

Multiply $3$ by $- 36$ .

$21 y + 39 = - 108$

Move all terms not containing $y$ to the right side of the equation.

Subtract $39$ from both sides of the equation.

$21 y = - 108 - 39$

Subtract $39$ from $- 108$ .

$21 y = - 147$

Divide each term in $21 y = - 147$ by $21$ and simplify.

Divide each term in $21 y = - 147$ by $21$ .

$\frac{21 y}{21} = \frac{- 147}{21}$

Simplify the left side.

Cancel the common factor of $21$ .

Cancel the common factor.

$\frac{21 y}{21} = \frac{- 147}{21}$

Divide $y$ by $1$ .

$y = \frac{- 147}{21}$

Simplify the right side.

Divide $- 147$ by $21$ .

$y = - 7$

Solve for y 1/3(21y+39)=-36

Related Questions

Support LCMGCF.com by disabling your adblocker.