Solve for y 1/3y-x^2+2x=-5

$\frac{1}{3} y - x^{2} + 2 x = - 5$

Combine $\frac{1}{3}$ and $y$ .

$\frac{y}{3} - x^{2} + 2 x = - 5$

Move all terms not containing $y$ to the right side of the equation.

Add $x^{2}$ to both sides of the equation.

$\frac{y}{3} + 2 x = - 5 + x^{2}$

Subtract $2 x$ from both sides of the equation.

$\frac{y}{3} = - 5 + x^{2} - 2 x$

Multiply both sides of the equation by $3$ .

$3 \frac{y}{3} = 3 (- 5 + x^{2} - 2 x)$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$3 \frac{y}{3} = 3 (- 5 + x^{2} - 2 x)$

Rewrite the expression.

$y = 3 (- 5 + x^{2} - 2 x)$

Simplify the right side.

Simplify $3 (- 5 + x^{2} - 2 x)$ .

Apply the distributive property.

$y = 3 \cdot - 5 + 3 x^{2} + 3 (- 2 x)$

Simplify.

Multiply $3$ by $- 5$ .

$y = - 15 + 3 x^{2} + 3 (- 2 x)$

Multiply $- 2$ by $3$ .

$y = - 15 + 3 x^{2} - 6 x$

Move $- 15$ .

$y = 3 x^{2} - 6 x - 15$