Solve for y 10+8y-2=10y-8

$10 + 8 y - 2 = 10 y - 8$

Subtract $2$ from $10$ .

$8 y + 8 = 10 y - 8$

Move all terms containing $y$ to the left side of the equation.

Subtract $10 y$ from both sides of the equation.

$8 y + 8 - 10 y = - 8$

Subtract $10 y$ from $8 y$ .

$- 2 y + 8 = - 8$

Move all terms not containing $y$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$- 2 y = - 8 - 8$

Subtract $8$ from $- 8$ .

$- 2 y = - 16$

Divide each term in $- 2 y = - 16$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 16$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 16}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 16}{- 2}$

Divide $y$ by $1$ .

$y = \frac{- 16}{- 2}$

Simplify the right side.

Divide $- 16$ by $- 2$ .

$y = 8$