Solve for y -10-y=3x

$- 10 - y = 3 x$

Step 1

Add $10$ to both sides of the equation.

$- y = 3 x + 10$

Step 2

Divide each term in $- y = 3 x + 10$ by $- 1$ and simplify.

Divide each term in $- y = 3 x + 10$ by $- 1$ .

$\frac{- y}{- 1} = \frac{3 x}{- 1} + \frac{10}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{3 x}{- 1} + \frac{10}{- 1}$

Divide $y$ by $1$ .

$y = \frac{3 x}{- 1} + \frac{10}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{3 x}{- 1}$ .

$y = - 1 \cdot (3 x) + \frac{10}{- 1}$

Rewrite $- 1 \cdot (3 x)$ as $- (3 x)$ .

$y = - (3 x) + \frac{10}{- 1}$

Multiply $3$ by $- 1$ .

$y = - 3 x + \frac{10}{- 1}$

Divide $10$ by $- 1$ .

$y = - 3 x - 10$