Solve for y 10y-5(1+y)=3(2y-2)-20

$10 y - 5 (1 + y) = 3 (2 y - 2) - 20$

Simplify $10 y - 5 (1 + y)$ .

Simplify each term.

Apply the distributive property.

$10 y - 5 \cdot 1 - 5 y = 3 (2 y - 2) - 20$

Multiply $- 5$ by $1$ .

$10 y - 5 - 5 y = 3 (2 y - 2) - 20$

Subtract $5 y$ from $10 y$ .

$5 y - 5 = 3 (2 y - 2) - 20$

Simplify $3 (2 y - 2) - 20$ .

Simplify each term.

Apply the distributive property.

$5 y - 5 = 3 (2 y) + 3 \cdot - 2 - 20$

Multiply $2$ by $3$ .

$5 y - 5 = 6 y + 3 \cdot - 2 - 20$

Multiply $3$ by $- 2$ .

$5 y - 5 = 6 y - 6 - 20$

Subtract $20$ from $- 6$ .

$5 y - 5 = 6 y - 26$

Move all terms containing $y$ to the left side of the equation.

Subtract $6 y$ from both sides of the equation.

$5 y - 5 - 6 y = - 26$

Subtract $6 y$ from $5 y$ .

$- y - 5 = - 26$

Move all terms not containing $y$ to the right side of the equation.

Add $5$ to both sides of the equation.

$- y = - 26 + 5$

Add $- 26$ and $5$ .

$- y = - 21$

Divide each term in $- y = - 21$ by $- 1$ and simplify.

Divide each term in $- y = - 21$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 21}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 21}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 21}{- 1}$

Simplify the right side.

Divide $- 21$ by $- 1$ .

$y = 21$