Solve for y 11y+4(y-5)=5(y+4(y-2))

$11 y + 4 (y - 5) = 5 (y + 4 (y - 2))$

Simplify $11 y + 4 (y - 5)$ .

Simplify each term.

Apply the distributive property.

$11 y + 4 y + 4 \cdot - 5 = 5 (y + 4 (y - 2))$

Multiply $4$ by $- 5$ .

$11 y + 4 y - 20 = 5 (y + 4 (y - 2))$

Add $11 y$ and $4 y$ .

$15 y - 20 = 5 (y + 4 (y - 2))$

Simplify $5 (y + 4 (y - 2))$ .

Simplify each term.

Apply the distributive property.

$15 y - 20 = 5 (y + 4 y + 4 \cdot - 2)$

Multiply $4$ by $- 2$ .

$15 y - 20 = 5 (y + 4 y - 8)$

Simplify terms.

Add $y$ and $4 y$ .

$15 y - 20 = 5 (5 y - 8)$

Apply the distributive property.

$15 y - 20 = 5 (5 y) + 5 \cdot - 8$

Multiply.

Multiply $5$ by $5$ .

$15 y - 20 = 25 y + 5 \cdot - 8$

Multiply $5$ by $- 8$ .

$15 y - 20 = 25 y - 40$

Move all terms containing $y$ to the left side of the equation.

Subtract $25 y$ from both sides of the equation.

$15 y - 20 - 25 y = - 40$

Subtract $25 y$ from $15 y$ .

$- 10 y - 20 = - 40$

Move all terms not containing $y$ to the right side of the equation.

Add $20$ to both sides of the equation.

$- 10 y = - 40 + 20$

Add $- 40$ and $20$ .

$- 10 y = - 20$

Divide each term in $- 10 y = - 20$ by $- 10$ and simplify.

Divide each term in $- 10 y = - 20$ by $- 10$ .

$\frac{- 10 y}{- 10} = \frac{- 20}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 y}{- 10} = \frac{- 20}{- 10}$

Divide $y$ by $1$ .

$y = \frac{- 20}{- 10}$

Simplify the right side.

Divide $- 20$ by $- 10$ .

$y = 2$

Solve for y 11y+4(y-5)=5(y+4(y-2))

Related Questions

Support LCMGCF.com by disabling your adblocker.