Solve for y -14+6x+7-2y=1

$- 14 + 6 x + 7 - 2 y = 1$

Step 1

Add $- 14$ and $7$ .

$6 x - 7 - 2 y = 1$

Step 2

Move all terms not containing $y$ to the right side of the equation.

Subtract $6 x$ from both sides of the equation.

$- 7 - 2 y = 1 - 6 x$

Add $7$ to both sides of the equation.

$- 2 y = 1 - 6 x + 7$

Add $1$ and $7$ .

$- 2 y = - 6 x + 8$

Step 3

Divide each term in $- 2 y = - 6 x + 8$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 6 x + 8$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 6 x}{- 2} + \frac{8}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 6 x}{- 2} + \frac{8}{- 2}$

Divide $y$ by $1$ .

$y = \frac{- 6 x}{- 2} + \frac{8}{- 2}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 6$ and $- 2$ .

Factor $- 2$ out of $- 6 x$ .

$y = \frac{- 2 (3 x)}{- 2} + \frac{8}{- 2}$

Cancel the common factors.

Factor $- 2$ out of $- 2$ .

$y = \frac{- 2 (3 x)}{- 2 (1)} + \frac{8}{- 2}$

Cancel the common factor.

$y = \frac{- 2 (3 x)}{- 2 \cdot 1} + \frac{8}{- 2}$

Rewrite the expression.

$y = \frac{3 x}{1} + \frac{8}{- 2}$

Divide $3 x$ by $1$ .

$y = 3 x + \frac{8}{- 2}$

Divide $8$ by $- 2$ .

$y = 3 x - 4$