Solve for y -15+4(2-5y)=-7(y-4)+4

$- 15 + 4 (2 - 5 y) = - 7 (y - 4) + 4$

Step 1

Simplify $- 15 + 4 (2 - 5 y)$ .

Simplify each term.

Apply the distributive property.

$- 15 + 4 \cdot 2 + 4 (- 5 y) = - 7 (y - 4) + 4$

Multiply $4$ by $2$ .

$- 15 + 8 + 4 (- 5 y) = - 7 (y - 4) + 4$

Multiply $- 5$ by $4$ .

$- 15 + 8 - 20 y = - 7 (y - 4) + 4$

Add $- 15$ and $8$ .

$- 7 - 20 y = - 7 (y - 4) + 4$

Step 2

Simplify $- 7 (y - 4) + 4$ .

Simplify each term.

Apply the distributive property.

$- 7 - 20 y = - 7 y - 7 \cdot - 4 + 4$

Multiply $- 7$ by $- 4$ .

$- 7 - 20 y = - 7 y + 28 + 4$

Add $28$ and $4$ .

$- 7 - 20 y = - 7 y + 32$

Step 3

Move all terms containing $y$ to the left side of the equation.

Add $7 y$ to both sides of the equation.

$- 7 - 20 y + 7 y = 32$

Add $- 20 y$ and $7 y$ .

$- 7 - 13 y = 32$

Step 4

Move all terms not containing $y$ to the right side of the equation.

Add $7$ to both sides of the equation.

$- 13 y = 32 + 7$

Add $32$ and $7$ .

$- 13 y = 39$

Step 5

Divide each term in $- 13 y = 39$ by $- 13$ and simplify.

Divide each term in $- 13 y = 39$ by $- 13$ .

$\frac{- 13 y}{- 13} = \frac{39}{- 13}$

Simplify the left side.

Cancel the common factor of $- 13$ .

Cancel the common factor.

$\frac{- 13 y}{- 13} = \frac{39}{- 13}$

Divide $y$ by $1$ .

$y = \frac{39}{- 13}$

Simplify the right side.

Divide $39$ by $- 13$ .

$y = - 3$

Solve for y -15+4(2-5y)=-7(y-4)+4

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