Solve for y 2+16y=3x+4

$2 + 16 y = 3 x + 4$

Step 1

Move all terms not containing $y$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$16 y = 3 x + 4 - 2$

Subtract $2$ from $4$ .

$16 y = 3 x + 2$

Step 2

Divide each term in $16 y = 3 x + 2$ by $16$ and simplify.

Divide each term in $16 y = 3 x + 2$ by $16$ .

$\frac{16 y}{16} = \frac{3 x}{16} + \frac{2}{16}$

Simplify the left side.

Cancel the common factor of $16$ .

Cancel the common factor.

$\frac{16 y}{16} = \frac{3 x}{16} + \frac{2}{16}$

Divide $y$ by $1$ .

$y = \frac{3 x}{16} + \frac{2}{16}$

Simplify the right side.

Cancel the common factor of $2$ and $16$ .

Factor $2$ out of $2$ .

$y = \frac{3 x}{16} + \frac{2 (1)}{16}$

Cancel the common factors.

Factor $2$ out of $16$ .

$y = \frac{3 x}{16} + \frac{2 \cdot 1}{2 \cdot 8}$

Cancel the common factor.

$y = \frac{3 x}{16} + \frac{2 \cdot 1}{2 \cdot 8}$

Rewrite the expression.

$y = \frac{3 x}{16} + \frac{1}{8}$