Solve for y 2((2y-1)+y)=5(y+3)

$2 ((2 y - 1) + y) = 5 (y + 3)$

Step 1

Simplify $2 (2 y - 1 + y)$ .

Rewrite.

$0 + 0 + 2 (2 y - 1 + y) = 5 (y + 3)$

Simplify by adding zeros.

$2 (2 y - 1 + y) = 5 (y + 3)$

Add $2 y$ and $y$ .

$2 (3 y - 1) = 5 (y + 3)$

Apply the distributive property.

$2 (3 y) + 2 \cdot - 1 = 5 (y + 3)$

Multiply.

Multiply $3$ by $2$ .

$6 y + 2 \cdot - 1 = 5 (y + 3)$

Multiply $2$ by $- 1$ .

$6 y - 2 = 5 (y + 3)$

Step 2

Simplify $5 (y + 3)$ .

Apply the distributive property.

$6 y - 2 = 5 y + 5 \cdot 3$

Multiply $5$ by $3$ .

$6 y - 2 = 5 y + 15$

Step 3

Move all terms containing $y$ to the left side of the equation.

Subtract $5 y$ from both sides of the equation.

$6 y - 2 - 5 y = 15$

Subtract $5 y$ from $6 y$ .

$y - 2 = 15$

Step 4

Move all terms not containing $y$ to the right side of the equation.

Add $2$ to both sides of the equation.

$y = 15 + 2$

Add $15$ and $2$ .

$y = 17$