Solve for y -2(2y+8)=4y+5+y

$- 2 (2 y + 8) = 4 y + 5 + y$

Since $y$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$4 y + 5 + y = - 2 (2 y + 8)$

Add $4 y$ and $y$ .

$5 y + 5 = - 2 (2 y + 8)$

Simplify $- 2 (2 y + 8)$ .

Apply the distributive property.

$5 y + 5 = - 2 (2 y) - 2 \cdot 8$

Multiply.

Multiply $2$ by $- 2$ .

$5 y + 5 = - 4 y - 2 \cdot 8$

Multiply $- 2$ by $8$ .

$5 y + 5 = - 4 y - 16$

Move all terms containing $y$ to the left side of the equation.

Add $4 y$ to both sides of the equation.

$5 y + 5 + 4 y = - 16$

Add $5 y$ and $4 y$ .

$9 y + 5 = - 16$

Move all terms not containing $y$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$9 y = - 16 - 5$

Subtract $5$ from $- 16$ .

$9 y = - 21$

Divide each term in $9 y = - 21$ by $9$ and simplify.

Divide each term in $9 y = - 21$ by $9$ .

$\frac{9 y}{9} = \frac{- 21}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 y}{9} = \frac{- 21}{9}$

Divide $y$ by $1$ .

$y = \frac{- 21}{9}$

Simplify the right side.

Cancel the common factor of $- 21$ and $9$ .

Factor $3$ out of $- 21$ .

$y = \frac{3 (- 7)}{9}$

Cancel the common factors.

Factor $3$ out of $9$ .

$y = \frac{3 \cdot - 7}{3 \cdot 3}$

Cancel the common factor.

$y = \frac{3 \cdot - 7}{3 \cdot 3}$

Rewrite the expression.

$y = \frac{- 7}{3}$

Move the negative in front of the fraction.

$y = - \frac{7}{3}$

The result can be shown in multiple forms.

Exact Form:

$y = - \frac{7}{3}$

Decimal Form:

$y = - 2.\overline{3}$

Mixed Number Form:

$y = - 2 \frac{1}{3}$

Solve for y -2(2y+8)=4y+5+y

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