Solve for y 2(-4y+x)=4

$2 (- 4 y + x) = 4$

Step 1

Divide each term in $2 (- 4 y + x) = 4$ by $2$ and simplify.

Divide each term in $2 (- 4 y + x) = 4$ by $2$ .

$\frac{2 (- 4 y + x)}{2} = \frac{4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (- 4 y + x)}{2} = \frac{4}{2}$

Divide $- 4 y + x$ by $1$ .

$- 4 y + x = \frac{4}{2}$

Simplify the right side.

Divide $4$ by $2$ .

$- 4 y + x = 2$

Step 2

Subtract $x$ from both sides of the equation.

$- 4 y = 2 - x$

Step 3

Divide each term in $- 4 y = 2 - x$ by $- 4$ and simplify.

Divide each term in $- 4 y = 2 - x$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{2}{- 4} + \frac{- x}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{2}{- 4} + \frac{- x}{- 4}$

Divide $y$ by $1$ .

$y = \frac{2}{- 4} + \frac{- x}{- 4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $2$ and $- 4$ .

Factor $2$ out of $2$ .

$y = \frac{2 (1)}{- 4} + \frac{- x}{- 4}$

Cancel the common factors.

Factor $2$ out of $- 4$ .

$y = \frac{2 \cdot 1}{2 \cdot - 2} + \frac{- x}{- 4}$

Cancel the common factor.

$y = \frac{2 \cdot 1}{2 \cdot - 2} + \frac{- x}{- 4}$

Rewrite the expression.

$y = \frac{1}{- 2} + \frac{- x}{- 4}$

Move the negative in front of the fraction.

$y = - \frac{1}{2} + \frac{- x}{- 4}$

Dividing two negative values results in a positive value.

$y = - \frac{1}{2} + \frac{x}{4}$