Solve for y 2(y+4)-3x=0

$2 (y + 4) - 3 x = 0$

Simplify each term.

Apply the distributive property.

$2 y + 2 \cdot 4 - 3 x = 0$

Multiply $2$ by $4$ .

$2 y + 8 - 3 x = 0$

Move all terms not containing $y$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$2 y - 3 x = - 8$

Add $3 x$ to both sides of the equation.

$2 y = - 8 + 3 x$

Divide each term in $2 y = - 8 + 3 x$ by $2$ and simplify.

Divide each term in $2 y = - 8 + 3 x$ by $2$ .

$\frac{2 y}{2} = \frac{- 8}{2} + \frac{3 x}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{- 8}{2} + \frac{3 x}{2}$

Divide $y$ by $1$ .

$y = \frac{- 8}{2} + \frac{3 x}{2}$

Simplify the right side.

Divide $- 8$ by $2$ .

$y = - 4 + \frac{3 x}{2}$