Solve for y 2x-3y=8

$2 x - 3 y = 8$

Step 1

Subtract $2 x$ from both sides of the equation.

$- 3 y = 8 - 2 x$

Step 2

Divide each term in $- 3 y = 8 - 2 x$ by $- 3$ and simplify.

Divide each term in $- 3 y = 8 - 2 x$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{8}{- 3} + \frac{- 2 x}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{8}{- 3} + \frac{- 2 x}{- 3}$

Divide $y$ by $1$ .

$y = \frac{8}{- 3} + \frac{- 2 x}{- 3}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$y = - \frac{8}{3} + \frac{- 2 x}{- 3}$

Dividing two negative values results in a positive value.

$y = - \frac{8}{3} + \frac{2 x}{3}$