Solve for y -2x+4y=8

$- 2 x + 4 y = 8$

Step 1

Add $2 x$ to both sides of the equation.

$4 y = 8 + 2 x$

Step 2

Divide each term in $4 y = 8 + 2 x$ by $4$ and simplify.

Divide each term in $4 y = 8 + 2 x$ by $4$ .

$\frac{4 y}{4} = \frac{8}{4} + \frac{2 x}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{8}{4} + \frac{2 x}{4}$

Divide $y$ by $1$ .

$y = \frac{8}{4} + \frac{2 x}{4}$

$y = \frac{8}{4} + \frac{2 x}{4}$

$y = \frac{8}{4} + \frac{2 x}{4}$

Simplify the right side.

Simplify each term.

Divide $8$ by $4$ .

$y = 2 + \frac{2 x}{4}$

Cancel the common factor of $2$ and $4$ .

Factor $2$ out of $2 x$ .

$y = 2 + \frac{2 (x)}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$y = 2 + \frac{2 x}{2 \cdot 2}$

Cancel the common factor.

$y = 2 + \frac{2 x}{2 \cdot 2}$

Rewrite the expression.

$y = 2 + \frac{x}{2}$

$y = 2 + \frac{x}{2}$

$y = 2 + \frac{x}{2}$

$y = 2 + \frac{x}{2}$

$y = 2 + \frac{x}{2}$

$y = 2 + \frac{x}{2}$

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