Solve for y 2x-y=-3

$2 x - y = - 3$

Step 1

Subtract $2 x$ from both sides of the equation.

$- y = - 3 - 2 x$

Step 2

Divide each term in $- y = - 3 - 2 x$ by $- 1$ and simplify.

Divide each term in $- y = - 3 - 2 x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 3}{- 1} + \frac{- 2 x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 3}{- 1} + \frac{- 2 x}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 3}{- 1} + \frac{- 2 x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 3$ by $- 1$ .

$y = 3 + \frac{- 2 x}{- 1}$

Move the negative one from the denominator of $\frac{- 2 x}{- 1}$ .

$y = 3 - 1 \cdot (- 2 x)$

Rewrite $- 1 \cdot (- 2 x)$ as $- (- 2 x)$ .

$y = 3 - (- 2 x)$

Multiply $- 2$ by $- 1$ .

$y = 3 + 2 x$