Solve for y 2y+3=3(y+7)

$2 y + 3 = 3 (y + 7)$

Step 1

Simplify $3 (y + 7)$ .

Rewrite.

$2 y + 3 = 0 + 0 + 3 (y + 7)$

Simplify by adding zeros.

$2 y + 3 = 3 (y + 7)$

Apply the distributive property.

$2 y + 3 = 3 y + 3 \cdot 7$

Multiply $3$ by $7$ .

$2 y + 3 = 3 y + 21$

Step 2

Move all terms containing $y$ to the left side of the equation.

Subtract $3 y$ from both sides of the equation.

$2 y + 3 - 3 y = 21$

Subtract $3 y$ from $2 y$ .

$- y + 3 = 21$

Step 3

Move all terms not containing $y$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- y = 21 - 3$

Subtract $3$ from $21$ .

$- y = 18$

Step 4

Divide each term in $- y = 18$ by $- 1$ and simplify.

Divide each term in $- y = 18$ by $- 1$ .

$\frac{- y}{- 1} = \frac{18}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{18}{- 1}$

Divide $y$ by $1$ .

$y = \frac{18}{- 1}$

Simplify the right side.

Divide $18$ by $- 1$ .

$y = - 18$