Solve for y 2y-7>8y+9

$2 y - 7 > 8 y + 9$

Step 1

Move all terms containing $y$ to the left side of the inequality.

Subtract $8 y$ from both sides of the inequality.

$2 y - 7 - 8 y > 9$

Subtract $8 y$ from $2 y$ .

$- 6 y - 7 > 9$

Step 2

Move all terms not containing $y$ to the right side of the inequality.

Add $7$ to both sides of the inequality.

$- 6 y > 9 + 7$

Add $9$ and $7$ .

$- 6 y > 16$

Step 3

Divide each term in $- 6 y > 16$ by $- 6$ and simplify.

Divide each term in $- 6 y > 16$ by $- 6$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 6 y}{- 6} < \frac{16}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 y}{- 6} < \frac{16}{- 6}$

Divide $y$ by $1$ .

$y < \frac{16}{- 6}$

Simplify the right side.

Cancel the common factor of $16$ and $- 6$ .

Factor $2$ out of $16$ .

$y < \frac{2 (8)}{- 6}$

Cancel the common factors.

Factor $2$ out of $- 6$ .

$y < \frac{2 \cdot 8}{2 \cdot - 3}$

Cancel the common factor.

$y < \frac{2 \cdot 8}{2 \cdot - 3}$

Rewrite the expression.

$y < \frac{8}{- 3}$

Move the negative in front of the fraction.

$y < - \frac{8}{3}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$y < - \frac{8}{3}$

Interval Notation:

$(- \infty, - \frac{8}{3})$

Solve for y 2y-7>8y+9

Related Questions

Support LCMGCF.com by disabling your adblocker.