Solve for y 3(2+y)-y=6+2(y+1)

$3 (2 + y) - y = 6 + 2 (y + 1)$

Simplify $3 (2 + y) - y$ .

Simplify each term.

Apply the distributive property.

$3 \cdot 2 + 3 y - y = 6 + 2 (y + 1)$

Multiply $3$ by $2$ .

$6 + 3 y - y = 6 + 2 (y + 1)$

Subtract $y$ from $3 y$ .

$6 + 2 y = 6 + 2 (y + 1)$

Simplify $6 + 2 (y + 1)$ .

Simplify each term.

Apply the distributive property.

$6 + 2 y = 6 + 2 y + 2 \cdot 1$

Multiply $2$ by $1$ .

$6 + 2 y = 6 + 2 y + 2$

Add $6$ and $2$ .

$6 + 2 y = 2 y + 8$

Move all terms containing $y$ to the left side of the equation.

Subtract $2 y$ from both sides of the equation.

$6 + 2 y - 2 y = 8$

Combine the opposite terms in $6 + 2 y - 2 y$ .

Subtract $2 y$ from $2 y$ .

$6 + 0 = 8$

Add $6$ and $0$ .

$6 = 8$

Since $6 \neq 8$ , there are no solutions.

No solution