Solve for y 3-2y=y-12

$3 - 2 y = y - 12$

Step 1

Move all terms containing $y$ to the left side of the equation.

Subtract $y$ from both sides of the equation.

$3 - 2 y - y = - 12$

Subtract $y$ from $- 2 y$ .

$3 - 3 y = - 12$

Step 2

Move all terms not containing $y$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- 3 y = - 12 - 3$

Subtract $3$ from $- 12$ .

$- 3 y = - 15$

Step 3

Divide each term in $- 3 y = - 15$ by $- 3$ and simplify.

Divide each term in $- 3 y = - 15$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{- 15}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{- 15}{- 3}$

Divide $y$ by $1$ .

$y = \frac{- 15}{- 3}$

Simplify the right side.

Divide $- 15$ by $- 3$ .

$y = 5$