Solve for y 3(y+2)-16=8y

$3 (y + 2) - 16 = 8 y$

Step 1

Simplify $3 (y + 2) - 16$ .

Simplify each term.

Apply the distributive property.

$3 y + 3 \cdot 2 - 16 = 8 y$

Multiply $3$ by $2$ .

$3 y + 6 - 16 = 8 y$

Subtract $16$ from $6$ .

$3 y - 10 = 8 y$

Step 2

Move all terms containing $y$ to the left side of the equation.

Subtract $8 y$ from both sides of the equation.

$3 y - 10 - 8 y = 0$

Subtract $8 y$ from $3 y$ .

$- 5 y - 10 = 0$

Step 3

Add $10$ to both sides of the equation.

$- 5 y = 10$

Step 4

Divide each term in $- 5 y = 10$ by $- 5$ and simplify.

Divide each term in $- 5 y = 10$ by $- 5$ .

$\frac{- 5 y}{- 5} = \frac{10}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 y}{- 5} = \frac{10}{- 5}$

Divide $y$ by $1$ .

$y = \frac{10}{- 5}$

Simplify the right side.

Divide $10$ by $- 5$ .

$y = - 2$