Solve for y 3(y-3)=6y

$3 (y - 3) = 6 y$

Step 1

Simplify $3 (y - 3)$ .

Rewrite.

$0 + 0 + 3 (y - 3) = 6 y$

Simplify by adding zeros.

$3 (y - 3) = 6 y$

Apply the distributive property.

$3 y + 3 \cdot - 3 = 6 y$

Multiply $3$ by $- 3$ .

$3 y - 9 = 6 y$

Step 2

Move all terms containing $y$ to the left side of the equation.

Subtract $6 y$ from both sides of the equation.

$3 y - 9 - 6 y = 0$

Subtract $6 y$ from $3 y$ .

$- 3 y - 9 = 0$

Step 3

Add $9$ to both sides of the equation.

$- 3 y = 9$

Step 4

Divide each term in $- 3 y = 9$ by $- 3$ and simplify.

Divide each term in $- 3 y = 9$ by $- 3$ .

$\frac{- 3 y}{- 3} = \frac{9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} = \frac{9}{- 3}$

Divide $y$ by $1$ .

$y = \frac{9}{- 3}$

Simplify the right side.

Divide $9$ by $- 3$ .

$y = - 3$